(2x^2-x+6)-2(x^2-3x+5)=11

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Solution for (2x^2-x+6)-2(x^2-3x+5)=11 equation:


Simplifying
(2x2 + -1x + 6) + -2(x2 + -3x + 5) = 11

Reorder the terms:
(6 + -1x + 2x2) + -2(x2 + -3x + 5) = 11

Remove parenthesis around (6 + -1x + 2x2)
6 + -1x + 2x2 + -2(x2 + -3x + 5) = 11

Reorder the terms:
6 + -1x + 2x2 + -2(5 + -3x + x2) = 11
6 + -1x + 2x2 + (5 * -2 + -3x * -2 + x2 * -2) = 11
6 + -1x + 2x2 + (-10 + 6x + -2x2) = 11

Reorder the terms:
6 + -10 + -1x + 6x + 2x2 + -2x2 = 11

Combine like terms: 6 + -10 = -4
-4 + -1x + 6x + 2x2 + -2x2 = 11

Combine like terms: -1x + 6x = 5x
-4 + 5x + 2x2 + -2x2 = 11

Combine like terms: 2x2 + -2x2 = 0
-4 + 5x + 0 = 11
-4 + 5x = 11

Solving
-4 + 5x = 11

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 5x = 11 + 4

Combine like terms: -4 + 4 = 0
0 + 5x = 11 + 4
5x = 11 + 4

Combine like terms: 11 + 4 = 15
5x = 15

Divide each side by '5'.
x = 3

Simplifying
x = 3

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